Distance from Clarksburg to Sint-Andries
The shortest distance (air line) between Clarksburg and Sint-Andries is 3,801.16 mi (6,117.37 km).
How far is Clarksburg from Sint-Andries
Clarksburg is located in Maryland, United States within 39° 13' 28.56" N -78° 44' 2.76" W (39.2246, -77.2659) coordinates. The local time in Clarksburg is 07:56 (01.02.2025)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 13:56 (01.02.2025)
The calculated flying distance from Sint-Andries to Sint-Andries is 3,801.16 miles which is equal to 6,117.37 km.
Clarksburg, Maryland, United States
Related Distances from Clarksburg
Sint-Andries, Arr. Brugge, Belgium