Distance from Clervaux to Sannicolau Mare
The shortest distance (air line) between Clervaux and Sannicolau Mare is 725.92 mi (1,168.26 km).
How far is Clervaux from Sannicolau Mare
Clervaux is located in Luxembourg, Luxembourg within 50° 2' 60" N 6° 1' 59.88" E (50.0500, 6.0333) coordinates. The local time in Clervaux is 05:42 (07.02.2025)
Sannicolau Mare is located in Timiş, Romania within 46° 3' 48.96" N 20° 36' 45" E (46.0636, 20.6125) coordinates. The local time in Sannicolau Mare is 06:42 (07.02.2025)
The calculated flying distance from Sannicolau Mare to Sannicolau Mare is 725.92 miles which is equal to 1,168.26 km.
Clervaux, Luxembourg, Luxembourg
Related Distances from Clervaux
Cities | Distance |
---|---|
Clervaux to Wiltz | 7.27 mi (11.70 km) |
Clervaux to Vianden | 11.16 mi (17.96 km) |
Clervaux to Diekirch | 13.71 mi (22.07 km) |
Clervaux to Redange-sur-Attert | 20.69 mi (33.30 km) |
Clervaux to Mersch | 20.94 mi (33.70 km) |
Clervaux to Echternach | 23.86 mi (38.41 km) |
Clervaux to Capellen | 28.09 mi (45.21 km) |
Clervaux to Luxembourg | 30.60 mi (49.25 km) |
Clervaux to Grevenmacher | 31.34 mi (50.44 km) |
Clervaux to Differdange | 37.01 mi (59.56 km) |
Clervaux to Remich | 37.97 mi (61.10 km) |
Clervaux to Esch-sur-Alzette | 38.29 mi (61.62 km) |
Clervaux to Dudelange | 39.22 mi (63.12 km) |
Sannicolau Mare, Timiş, Romania