Distance from Cleveland Heights to Aleksandrow Lodzki
The shortest distance (air line) between Cleveland Heights and Aleksandrow Lodzki is 4,442.48 mi (7,149.48 km).
How far is Cleveland Heights from Aleksandrow Lodzki
Cleveland Heights is located in Ohio, United States within 41° 30' 40.68" N -82° 26' 11.04" W (41.5113, -81.5636) coordinates. The local time in Cleveland Heights is 07:39 (16.05.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 13:39 (16.05.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,442.48 miles which is equal to 7,149.48 km.
Cleveland Heights, Ohio, United States
Related Distances from Cleveland Heights
Aleksandrow Lodzki, Łódzki, Poland