Distance from Cleveland Heights to Sansepolcro
The shortest distance (air line) between Cleveland Heights and Sansepolcro is 4,494.75 mi (7,233.61 km).
How far is Cleveland Heights from Sansepolcro
Cleveland Heights is located in Ohio, United States within 41° 30' 40.68" N -82° 26' 11.04" W (41.5113, -81.5636) coordinates. The local time in Cleveland Heights is 05:43 (10.05.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 11:43 (10.05.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,494.75 miles which is equal to 7,233.61 km.
Cleveland Heights, Ohio, United States