Distance from Copiague to Aleksandrovac
The shortest distance (air line) between Copiague and Aleksandrovac is 4,565.16 mi (7,346.92 km).
How far is Copiague from Aleksandrovac
Copiague is located in New York, United States within 40° 40' 14.52" N -74° 36' 28.08" W (40.6707, -73.3922) coordinates. The local time in Copiague is 07:31 (11.01.2026)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 13:31 (11.01.2026)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 4,565.16 miles which is equal to 7,346.92 km.
Copiague, New York, United States
Related Distances from Copiague
Aleksandrovac, Rasinska oblast, Serbia