Distance from Cristuru Secuiesc to Abbots Langley
The shortest distance (air line) between Cristuru Secuiesc and Abbots Langley is 1,205.59 mi (1,940.22 km).
How far is Cristuru Secuiesc from Abbots Langley
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 03:21 (26.05.2025)
Abbots Langley is located in Hertfordshire, United Kingdom within 51° 42' 3.6" N -1° 35' 2.4" W (51.7010, -0.4160) coordinates. The local time in Abbots Langley is 01:21 (26.05.2025)
The calculated flying distance from Abbots Langley to Abbots Langley is 1,205.59 miles which is equal to 1,940.22 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Abbots Langley, Hertfordshire, United Kingdom