Distance from Cristuru Secuiesc to Albuquerque
The shortest distance (air line) between Cristuru Secuiesc and Albuquerque is 6,060.83 mi (9,753.96 km).
How far is Cristuru Secuiesc from Albuquerque
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 09:14 (09.06.2025)
Albuquerque is located in New Mexico, United States within 35° 6' 19.44" N -107° 21' 12.6" W (35.1054, -106.6465) coordinates. The local time in Albuquerque is 00:14 (09.06.2025)
The calculated flying distance from Albuquerque to Albuquerque is 6,060.83 miles which is equal to 9,753.96 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Albuquerque, New Mexico, United States