Distance from Cristuru Secuiesc to Campbellsville
The shortest distance (air line) between Cristuru Secuiesc and Campbellsville is 5,229.81 mi (8,416.57 km).
How far is Cristuru Secuiesc from Campbellsville
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 00:11 (06.01.2026)
Campbellsville is located in Kentucky, United States within 37° 20' 40.2" N -86° 38' 56.04" W (37.3445, -85.3511) coordinates. The local time in Campbellsville is 17:11 (05.01.2026)
The calculated flying distance from Campbellsville to Campbellsville is 5,229.81 miles which is equal to 8,416.57 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Campbellsville, Kentucky, United States