Distance from Cristuru Secuiesc to La Puebla del Rio
The shortest distance (air line) between Cristuru Secuiesc and La Puebla del Rio is 1,705.23 mi (2,744.30 km).
How far is Cristuru Secuiesc from La Puebla del Rio
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 09:24 (28.05.2025)
La Puebla del Rio is located in Sevilla, Spain within 37° 16' 0.12" N -7° 57' 0" W (37.2667, -6.0500) coordinates. The local time in La Puebla del Rio is 08:24 (28.05.2025)
The calculated flying distance from La Puebla del Rio to La Puebla del Rio is 1,705.23 miles which is equal to 2,744.30 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
La Puebla del Rio, Sevilla, Spain