Distance from Cristuru Secuiesc to Palm Harbor
The shortest distance (air line) between Cristuru Secuiesc and Palm Harbor is 5,605.84 mi (9,021.73 km).
How far is Cristuru Secuiesc from Palm Harbor
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 17:15 (18.12.2025)
Palm Harbor is located in Florida, United States within 28° 5' 4.92" N -83° 15' 6.84" W (28.0847, -82.7481) coordinates. The local time in Palm Harbor is 10:15 (18.12.2025)
The calculated flying distance from Palm Harbor to Palm Harbor is 5,605.84 miles which is equal to 9,021.73 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Palm Harbor, Florida, United States