Distance from Cristuru Secuiesc to Poughkeepsie
The shortest distance (air line) between Cristuru Secuiesc and Poughkeepsie is 4,587.14 mi (7,382.29 km).
How far is Cristuru Secuiesc from Poughkeepsie
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 05:46 (23.06.2025)
Poughkeepsie is located in New York, United States within 41° 41' 42" N -74° 4' 44.04" W (41.6950, -73.9211) coordinates. The local time in Poughkeepsie is 22:46 (22.06.2025)
The calculated flying distance from Poughkeepsie to Poughkeepsie is 4,587.14 miles which is equal to 7,382.29 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Poughkeepsie, New York, United States