Distance from Cristuru Secuiesc to Robbinsdale
The shortest distance (air line) between Cristuru Secuiesc and Robbinsdale is 5,097.70 mi (8,203.95 km).
How far is Cristuru Secuiesc from Robbinsdale
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 11:57 (23.06.2025)
Robbinsdale is located in Minnesota, United States within 45° 1' 33.96" N -94° 40' 0.48" W (45.0261, -93.3332) coordinates. The local time in Robbinsdale is 03:57 (23.06.2025)
The calculated flying distance from Robbinsdale to Robbinsdale is 5,097.70 miles which is equal to 8,203.95 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Robbinsdale, Minnesota, United States