Distance from Cristuru Secuiesc to Six-Fours-les-Plages
The shortest distance (air line) between Cristuru Secuiesc and Six-Fours-les-Plages is 966.55 mi (1,555.51 km).
How far is Cristuru Secuiesc from Six-Fours-les-Plages
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 18:38 (04.12.2024)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 17:38 (04.12.2024)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 966.55 miles which is equal to 1,555.51 km.
Cristuru Secuiesc, Harghita, Romania
Related Distances from Cristuru Secuiesc
Six-Fours-les-Plages, Var, France