Distance from Cuyahoga Falls to Sansepolcro
The shortest distance (air line) between Cuyahoga Falls and Sansepolcro is 4,507.48 mi (7,254.08 km).
How far is Cuyahoga Falls from Sansepolcro
Cuyahoga Falls is located in Ohio, United States within 41° 9' 50.76" N -82° 28' 45.48" W (41.1641, -81.5207) coordinates. The local time in Cuyahoga Falls is 10:45 (26.02.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 16:45 (26.02.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,507.48 miles which is equal to 7,254.08 km.
Cuyahoga Falls, Ohio, United States