Distance from Dent to Aleksandrow Lodzki
The shortest distance (air line) between Dent and Aleksandrow Lodzki is 4,670.50 mi (7,516.45 km).
How far is Dent from Aleksandrow Lodzki
Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 21:57 (10.03.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 03:57 (11.03.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,670.50 miles which is equal to 7,516.45 km.
Related Distances from Dent
Aleksandrow Lodzki, Łódzki, Poland