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      Distance from Dent to San Ferdinando di Puglia

      The shortest distance (air line) between Dent and San Ferdinando di Puglia is 4,976.07 mi (8,008.22 km).

      How far is Dent from San Ferdinando di Puglia

      Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 13:35 (05.03.2025)

      San Ferdinando di Puglia is located in Barletta-Andria-Trani, Italy within 41° 17' 60" N 16° 4' 0.12" E (41.3000, 16.0667) coordinates. The local time in San Ferdinando di Puglia is 19:35 (05.03.2025)

      The calculated flying distance from San Ferdinando di Puglia to San Ferdinando di Puglia is 4,976.07 miles which is equal to 8,008.22 km.

      Dent, Ohio, United States

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      San Ferdinando di Puglia, Barletta-Andria-Trani, Italy

      Related Distances to San Ferdinando di Puglia