Distance from Dent to Sansepolcro
The shortest distance (air line) between Dent and Sansepolcro is 4,721.98 mi (7,599.29 km).
How far is Dent from Sansepolcro
Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 13:42 (05.03.2025)
Sansepolcro is located in Arezzo, Italy within 43° 34' 32.16" N 12° 8' 38.04" E (43.5756, 12.1439) coordinates. The local time in Sansepolcro is 19:42 (05.03.2025)
The calculated flying distance from Sansepolcro to Sansepolcro is 4,721.98 miles which is equal to 7,599.29 km.