Distance from Dent to Steenokkerzeel
The shortest distance (air line) between Dent and Steenokkerzeel is 4,156.48 mi (6,689.21 km).
How far is Dent from Steenokkerzeel
Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 17:08 (01.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 23:08 (01.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,156.48 miles which is equal to 6,689.21 km.
Related Distances from Dent
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium