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      Distance from Dent to Villeneuve-Saint-Georges

      The shortest distance (air line) between Dent and Villeneuve-Saint-Georges is 4,142.18 mi (6,666.20 km).

      How far is Dent from Villeneuve-Saint-Georges

      Dent is located in Ohio, United States within 39° 11' 29.4" N -85° 20' 23.64" W (39.1915, -84.6601) coordinates. The local time in Dent is 16:26 (20.02.2025)

      Villeneuve-Saint-Georges is located in Val-de-Marne, France within 48° 43' 57" N 2° 26' 58.92" E (48.7325, 2.4497) coordinates. The local time in Villeneuve-Saint-Georges is 22:26 (20.02.2025)

      The calculated flying distance from Villeneuve-Saint-Georges to Villeneuve-Saint-Georges is 4,142.18 miles which is equal to 6,666.20 km.

      Dent, Ohio, United States

      Related Distances from Dent

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      Dent to San Diego (California)1,856.08 mi (2,987.07 km)
      Dent to Los Angeles (California)1,891.95 mi (3,044.80 km)
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      Dent to Detroit (Michigan)235.10 mi (378.36 km)
      Dent to Chicago (Illinois)242.24 mi (389.85 km)
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      Dent to Baltimore (Maryland)430.43 mi (692.71 km)
      Dent to Philadelphia (Pennsylvania)510.03 mi (820.81 km)
      Dent to Brooklyn (New York)576.04 mi (927.05 km)
      Dent to New York (New York)577.69 mi (929.70 km)
      Dent to Queens (New York)584.77 mi (941.10 km)
      Dent to Minneapolis (Minnesota)594.29 mi (956.41 km)

      Villeneuve-Saint-Georges, Val-de-Marne, France

      Related Distances to Villeneuve-Saint-Georges