Distance from Dickinson to Diepenbeek
The shortest distance (air line) between Dickinson and Diepenbeek is 4,450.17 mi (7,161.86 km).
How far is Dickinson from Diepenbeek
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 05:33 (03.04.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 13:33 (03.04.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 4,450.17 miles which is equal to 7,161.86 km.
Dickinson, North Dakota, United States
Related Distances from Dickinson
Diepenbeek, Arr. Hasselt, Belgium