Distance from Dickinson to Dimitrovgrad
The shortest distance (air line) between Dickinson and Dimitrovgrad is 5,391.47 mi (8,676.74 km).
How far is Dickinson from Dimitrovgrad
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 19:31 (18.04.2025)
Dimitrovgrad is located in Pirotska oblast, Serbia within 43° 1' 0.12" N 22° 46' 59.88" E (43.0167, 22.7833) coordinates. The local time in Dimitrovgrad is 03:31 (19.04.2025)
The calculated flying distance from Dimitrovgrad to Dimitrovgrad is 5,391.47 miles which is equal to 8,676.74 km.
Dickinson, North Dakota, United States
Related Distances from Dickinson
Dimitrovgrad, Pirotska oblast, Serbia