Distance from Dickinson to Scherpenheuvel
The shortest distance (air line) between Dickinson and Scherpenheuvel is 4,431.27 mi (7,131.45 km).
How far is Dickinson from Scherpenheuvel
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 15:47 (15.11.2024)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 23:47 (15.11.2024)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 4,431.27 miles which is equal to 7,131.45 km.
Dickinson, North Dakota, United States
Related Distances from Dickinson
Scherpenheuvel, Arr. Leuven, Belgium