Distance from Dickinson to Sint-Andries
The shortest distance (air line) between Dickinson and Sint-Andries is 4,365.66 mi (7,025.85 km).
How far is Dickinson from Sint-Andries
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 15:53 (15.11.2024)
Sint-Andries is located in Arr. Brugge, Belgium within 51° 12' 0" N 3° 10' 59.88" E (51.2000, 3.1833) coordinates. The local time in Sint-Andries is 23:53 (15.11.2024)
The calculated flying distance from Sint-Andries to Sint-Andries is 4,365.66 miles which is equal to 7,025.85 km.
Dickinson, North Dakota, United States
Related Distances from Dickinson
Sint-Andries, Arr. Brugge, Belgium