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      Distance from Dickinson to Sint-Pieters-Leeuw

      The shortest distance (air line) between Dickinson and Sint-Pieters-Leeuw is 4,419.23 mi (7,112.06 km).

      How far is Dickinson from Sint-Pieters-Leeuw

      Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 07:34 (16.04.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 15:34 (16.04.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,419.23 miles which is equal to 7,112.06 km.

      Dickinson, North Dakota, United States

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw