Distance from Dickinson to Sveti Ivan Zelina
The shortest distance (air line) between Dickinson and Sveti Ivan Zelina is 5,036.10 mi (8,104.82 km).
How far is Dickinson from Sveti Ivan Zelina
Dickinson is located in North Dakota, United States within 46° 53' 30.48" N -103° 12' 27" W (46.8918, -102.7925) coordinates. The local time in Dickinson is 01:22 (16.11.2024)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 09:22 (16.11.2024)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,036.10 miles which is equal to 8,104.82 km.
Dickinson, North Dakota, United States
Related Distances from Dickinson
Sveti Ivan Zelina, Zagrebačka županija, Croatia