Distance from Diekirch to Alexander City
The shortest distance (air line) between Diekirch and Alexander City is 4,607.46 mi (7,414.99 km).
How far is Diekirch from Alexander City
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 08:14 (10.03.2025)
Alexander City is located in Alabama, United States within 32° 55' 22.44" N -86° 3' 51.12" W (32.9229, -85.9358) coordinates. The local time in Alexander City is 01:14 (10.03.2025)
The calculated flying distance from Alexander City to Alexander City is 4,607.46 miles which is equal to 7,414.99 km.
Diekirch, Luxembourg, Luxembourg
Related Distances from Diekirch
| Cities | Distance |
|---|---|
| Diekirch to Vianden | 5.06 mi (8.14 km) |
| Diekirch to Mersch | 8.54 mi (13.75 km) |
| Diekirch to Wiltz | 12.05 mi (19.39 km) |
| Diekirch to Echternach | 12.43 mi (20.01 km) |
| Diekirch to Clervaux | 13.71 mi (22.07 km) |
| Diekirch to Redange-sur-Attert | 13.88 mi (22.33 km) |
| Diekirch to Capellen | 17.16 mi (27.62 km) |
| Diekirch to Luxembourg | 17.75 mi (28.57 km) |
| Diekirch to Grevenmacher | 18.15 mi (29.22 km) |
| Diekirch to Remich | 24.25 mi (39.03 km) |
| Diekirch to Differdange | 26.67 mi (42.93 km) |
| Diekirch to Dudelange | 26.79 mi (43.11 km) |
| Diekirch to Esch-sur-Alzette | 26.83 mi (43.18 km) |
Alexander City, Alabama, United States