Distance from Diekirch to Lake Oswego
The shortest distance (air line) between Diekirch and Lake Oswego is 5,174.54 mi (8,327.61 km).
How far is Diekirch from Lake Oswego
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 20:32 (19.03.2025)
Lake Oswego is located in Oregon, United States within 45° 24' 46.44" N -123° 17' 58.56" W (45.4129, -122.7004) coordinates. The local time in Lake Oswego is 11:32 (19.03.2025)
The calculated flying distance from Lake Oswego to Lake Oswego is 5,174.54 miles which is equal to 8,327.61 km.
Diekirch, Luxembourg, Luxembourg
Related Distances from Diekirch
| Cities | Distance |
|---|---|
| Diekirch to Vianden | 5.06 mi (8.14 km) |
| Diekirch to Mersch | 8.54 mi (13.75 km) |
| Diekirch to Wiltz | 12.05 mi (19.39 km) |
| Diekirch to Echternach | 12.43 mi (20.01 km) |
| Diekirch to Clervaux | 13.71 mi (22.07 km) |
| Diekirch to Redange-sur-Attert | 13.88 mi (22.33 km) |
| Diekirch to Capellen | 17.16 mi (27.62 km) |
| Diekirch to Luxembourg | 17.75 mi (28.57 km) |
| Diekirch to Grevenmacher | 18.15 mi (29.22 km) |
| Diekirch to Remich | 24.25 mi (39.03 km) |
| Diekirch to Differdange | 26.67 mi (42.93 km) |
| Diekirch to Dudelange | 26.79 mi (43.11 km) |
| Diekirch to Esch-sur-Alzette | 26.83 mi (43.18 km) |
Lake Oswego, Oregon, United States