Distance from Diekirch to Seven Hills
The shortest distance (air line) between Diekirch and Seven Hills is 4,036.25 mi (6,495.72 km).
How far is Diekirch from Seven Hills
Diekirch is located in Luxembourg, Luxembourg within 49° 52' 5.16" N 6° 9' 24.12" E (49.8681, 6.1567) coordinates. The local time in Diekirch is 10:48 (26.04.2025)
Seven Hills is located in Ohio, United States within 41° 22' 49.08" N -82° 19' 35.04" W (41.3803, -81.6736) coordinates. The local time in Seven Hills is 04:48 (26.04.2025)
The calculated flying distance from Seven Hills to Seven Hills is 4,036.25 miles which is equal to 6,495.72 km.
Diekirch, Luxembourg, Luxembourg
Related Distances from Diekirch
| Cities | Distance |
|---|---|
| Diekirch to Vianden | 5.06 mi (8.14 km) |
| Diekirch to Mersch | 8.54 mi (13.75 km) |
| Diekirch to Wiltz | 12.05 mi (19.39 km) |
| Diekirch to Echternach | 12.43 mi (20.01 km) |
| Diekirch to Clervaux | 13.71 mi (22.07 km) |
| Diekirch to Redange-sur-Attert | 13.88 mi (22.33 km) |
| Diekirch to Capellen | 17.16 mi (27.62 km) |
| Diekirch to Luxembourg | 17.75 mi (28.57 km) |
| Diekirch to Grevenmacher | 18.15 mi (29.22 km) |
| Diekirch to Remich | 24.25 mi (39.03 km) |
| Diekirch to Differdange | 26.67 mi (42.93 km) |
| Diekirch to Dudelange | 26.79 mi (43.11 km) |
| Diekirch to Esch-sur-Alzette | 26.83 mi (43.18 km) |
Seven Hills, Ohio, United States