Distance from Diepenbeek to Sankt Polten
The shortest distance (air line) between Diepenbeek and Sankt Polten is 493.42 mi (794.09 km).
How far is Diepenbeek from Sankt Polten
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 02:10 (23.11.2024)
Sankt Polten is located in Sankt Pölten, Austria within 48° 12' 0" N 15° 37' 0.12" E (48.2000, 15.6167) coordinates. The local time in Sankt Polten is 02:10 (23.11.2024)
The calculated flying distance from Sankt Polten to Sankt Polten is 493.42 miles which is equal to 794.09 km.
Diepenbeek, Arr. Hasselt, Belgium
Related Distances from Diepenbeek
Sankt Polten, Sankt Pölten, Austria