Distance from Diepenbeek to Vetraz-Monthoux
The shortest distance (air line) between Diepenbeek and Vetraz-Monthoux is 329.25 mi (529.88 km).
How far is Diepenbeek from Vetraz-Monthoux
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 05:18 (30.11.2024)
Vetraz-Monthoux is located in Haute-Savoie, France within 46° 10' 27.12" N 6° 15' 18" E (46.1742, 6.2550) coordinates. The local time in Vetraz-Monthoux is 05:18 (30.11.2024)
The calculated flying distance from Vetraz-Monthoux to Vetraz-Monthoux is 329.25 miles which is equal to 529.88 km.
Diepenbeek, Arr. Hasselt, Belgium
Related Distances from Diepenbeek
Vetraz-Monthoux, Haute-Savoie, France