Distance from Dix Hills to Bad Sassendorf
The shortest distance (air line) between Dix Hills and Bad Sassendorf is 3,761.78 mi (6,054.00 km).
How far is Dix Hills from Bad Sassendorf
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 15:01 (05.02.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 21:01 (05.02.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 3,761.78 miles which is equal to 6,054.00 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Bad Sassendorf, Soest, Germany