Distance from Dix Hills to Bad Sooden-Allendorf
The shortest distance (air line) between Dix Hills and Bad Sooden-Allendorf is 3,841.76 mi (6,182.71 km).
How far is Dix Hills from Bad Sooden-Allendorf
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 18:45 (10.02.2025)
Bad Sooden-Allendorf is located in Werra-Meißner-Kreis, Germany within 51° 16' 59.88" N 9° 58' 59.88" E (51.2833, 9.9833) coordinates. The local time in Bad Sooden-Allendorf is 00:45 (11.02.2025)
The calculated flying distance from Bad Sooden-Allendorf to Bad Sooden-Allendorf is 3,841.76 miles which is equal to 6,182.71 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Bad Sooden-Allendorf, Werra-Meißner-Kreis, Germany