Distance from Dix Hills to Boleslawiec
The shortest distance (air line) between Dix Hills and Boleslawiec is 4,059.09 mi (6,532.48 km).
How far is Dix Hills from Boleslawiec
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 16:18 (25.02.2025)
Boleslawiec is located in Jeleniogórski, Poland within 51° 16' 0.12" N 15° 34' 0.12" E (51.2667, 15.5667) coordinates. The local time in Boleslawiec is 22:18 (25.02.2025)
The calculated flying distance from Boleslawiec to Boleslawiec is 4,059.09 miles which is equal to 6,532.48 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Boleslawiec, Jeleniogórski, Poland