Distance from Dix Hills to Diepenbeek
The shortest distance (air line) between Dix Hills and Diepenbeek is 3,669.70 mi (5,905.81 km).
How far is Dix Hills from Diepenbeek
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 05:51 (01.02.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 11:51 (01.02.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,669.70 miles which is equal to 5,905.81 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Diepenbeek, Arr. Hasselt, Belgium