Distance from Dix Hills to Drobeta-Turnu Severin
The shortest distance (air line) between Dix Hills and Drobeta-Turnu Severin is 4,576.71 mi (7,365.50 km).
How far is Dix Hills from Drobeta-Turnu Severin
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 14:37 (27.02.2025)
Drobeta-Turnu Severin is located in Mehedinţi, Romania within 44° 37' 59.88" N 22° 38' 60" E (44.6333, 22.6500) coordinates. The local time in Drobeta-Turnu Severin is 21:37 (27.02.2025)
The calculated flying distance from Drobeta-Turnu Severin to Drobeta-Turnu Severin is 4,576.71 miles which is equal to 7,365.50 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Drobeta-Turnu Severin, Mehedinţi, Romania