Distance from Dix Hills to Herenthout
The shortest distance (air line) between Dix Hills and Herenthout is 3,637.23 mi (5,853.56 km).
How far is Dix Hills from Herenthout
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 08:53 (01.02.2025)
Herenthout is located in Arr. Turnhout, Belgium within 51° 8' 60" N 4° 46' 0.12" E (51.1500, 4.7667) coordinates. The local time in Herenthout is 14:53 (01.02.2025)
The calculated flying distance from Herenthout to Herenthout is 3,637.23 miles which is equal to 5,853.56 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Herenthout, Arr. Turnhout, Belgium