Distance from Dix Hills to Janow Lubelski
The shortest distance (air line) between Dix Hills and Janow Lubelski is 4,336.18 mi (6,978.40 km).
How far is Dix Hills from Janow Lubelski
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 01:49 (26.02.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 07:49 (26.02.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,336.18 miles which is equal to 6,978.40 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Janow Lubelski, Puławski, Poland