Distance from Dix Hills to Koekelberg
The shortest distance (air line) between Dix Hills and Koekelberg is 3,626.76 mi (5,836.71 km).
How far is Dix Hills from Koekelberg
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 09:19 (01.02.2025)
Koekelberg is located in Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium within 50° 52' 0.12" N 4° 19' 59.88" E (50.8667, 4.3333) coordinates. The local time in Koekelberg is 15:19 (01.02.2025)
The calculated flying distance from Koekelberg to Koekelberg is 3,626.76 miles which is equal to 5,836.71 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Koekelberg, Arr. de Bruxelles-Capitale/Arr. Brussel-Hoofdstad, Belgium