Distance from Dix Hills to Lyaskovets
The shortest distance (air line) between Dix Hills and Lyaskovets is 4,762.56 mi (7,664.61 km).
How far is Dix Hills from Lyaskovets
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 20:42 (01.02.2025)
Lyaskovets is located in Veliko Tarnovo, Bulgaria within 43° 6' 0" N 25° 43' 0.12" E (43.1000, 25.7167) coordinates. The local time in Lyaskovets is 03:42 (02.02.2025)
The calculated flying distance from Lyaskovets to Lyaskovets is 4,762.56 miles which is equal to 7,664.61 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Lyaskovets, Veliko Tarnovo, Bulgaria