Distance from Dix Hills to Mercato San Severino
The shortest distance (air line) between Dix Hills and Mercato San Severino is 4,389.17 mi (7,063.68 km).
How far is Dix Hills from Mercato San Severino
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 08:18 (13.02.2025)
Mercato San Severino is located in Salerno, Italy within 40° 46' 59.88" N 14° 46' 0.12" E (40.7833, 14.7667) coordinates. The local time in Mercato San Severino is 14:18 (13.02.2025)
The calculated flying distance from Mercato San Severino to Mercato San Severino is 4,389.17 miles which is equal to 7,063.68 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Mercato San Severino, Salerno, Italy