Distance from Dix Hills to Opglabbeek
The shortest distance (air line) between Dix Hills and Opglabbeek is 3,672.72 mi (5,910.67 km).
How far is Dix Hills from Opglabbeek
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 08:06 (26.04.2025)
Opglabbeek is located in Arr. Maaseik, Belgium within 51° 2' 60" N 5° 34' 59.88" E (51.0500, 5.5833) coordinates. The local time in Opglabbeek is 14:06 (26.04.2025)
The calculated flying distance from Opglabbeek to Opglabbeek is 3,672.72 miles which is equal to 5,910.67 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Opglabbeek, Arr. Maaseik, Belgium