Distance from Dix Hills to Oranienburg
The shortest distance (air line) between Dix Hills and Oranienburg is 3,924.50 mi (6,315.87 km).
How far is Dix Hills from Oranienburg
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 17:33 (07.02.2025)
Oranienburg is located in Oberhavel, Germany within 52° 45' 15.84" N 13° 14' 12.84" E (52.7544, 13.2369) coordinates. The local time in Oranienburg is 23:33 (07.02.2025)
The calculated flying distance from Oranienburg to Oranienburg is 3,924.50 miles which is equal to 6,315.87 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Oranienburg, Oberhavel, Germany