Distance from Dix Hills to Osternienburg
The shortest distance (air line) between Dix Hills and Osternienburg is 3,906.11 mi (6,286.28 km).
How far is Dix Hills from Osternienburg
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 18:27 (07.02.2025)
Osternienburg is located in Anhalt-Bitterfeld, Germany within 51° 47' 60" N 12° 1' 0.12" E (51.8000, 12.0167) coordinates. The local time in Osternienburg is 00:27 (08.02.2025)
The calculated flying distance from Osternienburg to Osternienburg is 3,906.11 miles which is equal to 6,286.28 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Osternienburg, Anhalt-Bitterfeld, Germany