Distance from Dix Hills to Sassenberg
The shortest distance (air line) between Dix Hills and Sassenberg is 3,745.90 mi (6,028.45 km).
How far is Dix Hills from Sassenberg
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 17:36 (14.12.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 23:36 (14.12.2025)
The calculated flying distance from Sassenberg to Sassenberg is 3,745.90 miles which is equal to 6,028.45 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sassenberg, Warendorf, Germany