Distance from Dix Hills to Sendenhorst
The shortest distance (air line) between Dix Hills and Sendenhorst is 3,741.41 mi (6,021.22 km).
How far is Dix Hills from Sendenhorst
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 21:07 (12.02.2025)
Sendenhorst is located in Warendorf, Germany within 51° 50' 38.04" N 7° 49' 40.08" E (51.8439, 7.8278) coordinates. The local time in Sendenhorst is 03:07 (13.02.2025)
The calculated flying distance from Sendenhorst to Sendenhorst is 3,741.41 miles which is equal to 6,021.22 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sendenhorst, Warendorf, Germany