Distance from Dix Hills to Sentrupert
The shortest distance (air line) between Dix Hills and Sentrupert is 4,216.92 mi (6,786.47 km).
How far is Dix Hills from Sentrupert
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 05:59 (01.03.2025)
Sentrupert is located in Jugovzhodna Slovenija, Slovenia within 45° 58' 36.84" N 15° 5' 22.92" E (45.9769, 15.0897) coordinates. The local time in Sentrupert is 11:59 (01.03.2025)
The calculated flying distance from Sentrupert to Sentrupert is 4,216.92 miles which is equal to 6,786.47 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sentrupert, Jugovzhodna Slovenija, Slovenia