Distance from Dix Hills to Sint-Pieters-Leeuw
The shortest distance (air line) between Dix Hills and Sint-Pieters-Leeuw is 3,625.46 mi (5,834.61 km).
How far is Dix Hills from Sint-Pieters-Leeuw
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 16:49 (01.02.2025)
Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 22:49 (01.02.2025)
The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 3,625.46 miles which is equal to 5,834.61 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium