Distance from Dix Hills to Steenokkerzeel
The shortest distance (air line) between Dix Hills and Steenokkerzeel is 3,632.56 mi (5,846.04 km).
How far is Dix Hills from Steenokkerzeel
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 15:53 (01.02.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 21:53 (01.02.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 3,632.56 miles which is equal to 5,846.04 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium