Distance from Dix Hills to Sulzbach-Rosenberg
The shortest distance (air line) between Dix Hills and Sulzbach-Rosenberg is 3,964.90 mi (6,380.88 km).
How far is Dix Hills from Sulzbach-Rosenberg
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 10:36 (08.02.2025)
Sulzbach-Rosenberg is located in Amberg-Sulzbach, Germany within 49° 30' 0" N 11° 45' 0" E (49.5000, 11.7500) coordinates. The local time in Sulzbach-Rosenberg is 16:36 (08.02.2025)
The calculated flying distance from Sulzbach-Rosenberg to Sulzbach-Rosenberg is 3,964.90 miles which is equal to 6,380.88 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sulzbach-Rosenberg, Amberg-Sulzbach, Germany