Distance from Dix Hills to Sveti Ivan Zelina
The shortest distance (air line) between Dix Hills and Sveti Ivan Zelina is 4,265.28 mi (6,864.30 km).
How far is Dix Hills from Sveti Ivan Zelina
Dix Hills is located in New York, United States within 40° 48' 11.88" N -74° 39' 45" W (40.8033, -73.3375) coordinates. The local time in Dix Hills is 00:57 (02.02.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 06:57 (02.02.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 4,265.28 miles which is equal to 6,864.30 km.
Dix Hills, New York, United States
Related Distances from Dix Hills
Sveti Ivan Zelina, Zagrebačka županija, Croatia